16x^2+56x+33=0

Solution for 16x^2+56x+33=0 equation:

16x^2+56x+33=0

a = 16; b = 56; c = +33;
Δ = b2-4ac
Δ = 562-4·16·33
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-32}{2*16}=\frac{-88}{32}
=-2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+32}{2*16}=\frac{-24}{32}
=-3/4
$